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Sub Engineer (Electrical) Complete Preparation Guide & Solved Questions (2026) - Apex Rankers

PPSC Recruitment Examination Syllabus & Question Bank

3832 Total Questions
~5748 mins Read Time
3 Subject Areas
๐ŸŽฏ High-Yield Preparation Strategy

๐Ÿ“˜ Official Examination Scheme, Question Blueprint & Interview Masterclass

โœ“ 100% Comprehensive Guide

Sub Engineer (Electrical) Examination Preparation Guide

๐Ÿ”ท Job Title: Sub Engineer (Electrical)

๐Ÿ“Œ Department / Ministry: Government of the Punjab

๐Ÿ“Œ Scale / BPS: BS-14

๐Ÿ“Œ Case Number / AD: 07-RA/2026


๐Ÿ”ท 1. Official Examination Scheme & Mark Distribution

The examination for the position of Sub Engineer (Electrical) consists of a structured assessment designed to evaluate candidates' knowledge and skills relevant to the role. Below is the detailed examination scheme:

  • Total Questions: 100 MCQs
  • Duration: 90 minutes
  • Total Marks: 100
  • Passing Aggregate Threshold: 50% (i.e., 50 marks)

๐Ÿ“Œ Mark Distribution:

  • Part I: English/Analytical Skills (20%)
  • Weight: 20 Marks
  • Focus: Comprehension, grammar, vocabulary, and analytical reasoning.
  • Part II: Professional Core Subject (80%)
  • Weight: 80 Marks
  • Focus: Electrical engineering principles, laws, and applications.

๐Ÿ“Œ Negative Marking Rules:

  • A penalty of 0.25 marks will be deducted for each incorrect answer. Candidates should be strategic in their answering to minimize penalties.

๐Ÿ”ท 2. Topic-by-Topic Syllabus Breakdown & High-Yield Question Blueprint

The syllabus for the Sub Engineer (Electrical) position encompasses a wide range of topics. Below is a comprehensive breakdown of each area, including key concepts and examples of potential questions.

๐Ÿ“Œ A. Electrical Fundamentals

  • Concepts:
  • Ohm's Law
  • Kirchhoff's Laws
  • Power and Energy Calculations
  • Example Questions:
  • What is the relationship between voltage, current, and resistance as per Ohm's Law?
  • Calculate the total current flowing in a circuit with a 12V battery and a resistance of 4ฮฉ.

๐Ÿ“Œ B. Circuit Theory

  • Concepts:
  • Series and Parallel Circuits
  • Thevenin's and Norton's Theorems
  • AC vs. DC Circuits
  • Example Questions:
  • How do you calculate total resistance in a series circuit?
  • What is the significance of Thevenin's theorem in circuit analysis?

๐Ÿ“Œ C. Electrical Machines

  • Concepts:
  • Types of Motors (AC and DC)
  • Transformers: Operation and Efficiency
  • Induction and Synchronous Motors
  • Example Questions:
  • Explain the working principle of a transformer.
  • What are the differences between synchronous and asynchronous motors?

๐Ÿ“Œ D. Power Systems

  • Concepts:
  • Generation, Transmission, and Distribution
  • Power Factor and its Importance
  • Protection Systems (Fuses, Circuit Breakers)
  • Example Questions:
  • What is the role of a circuit breaker in a power system?
  • How does power factor affect the efficiency of electrical systems?

๐Ÿ“Œ E. Electrical Safety and Standards

  • Concepts:
  • Electrical Codes (IEC, NEC)
  • Safety Procedures and Equipment
  • Grounding and Bonding Techniques
  • Example Questions:
  • What are the safety measures to be taken while working on electrical installations?
  • Explain the importance of grounding in electrical systems.

๐Ÿ“Œ F. Instrumentation and Control

  • Concepts:
  • Types of Sensors and Transducers
  • Control Systems (PID Controllers)
  • Measurement Techniques
  • Example Questions:
  • Describe the working principle of a thermocouple.
  • What is the function of a PID controller in automation?

๐Ÿ”ท 3. MCQ Problem-Solving Tactics, Time Allocation & Elimination Shortcuts

To achieve a score of 85+ marks, candidates should adopt the following strategies:

๐Ÿ“Œ Time Management:

  • Time Budget: Aim to spend under 50 seconds per question. This allows for a thorough review of all questions within the allotted time.

๐Ÿ“Œ Smart Elimination:

  • Identify and eliminate clearly incorrect options first. This increases the probability of selecting the correct answer from the remaining choices.

๐Ÿ“Œ Handling Inverted Questions:

  • For questions framed as "Which of the following is NOT...", focus on identifying the correct statements first, then select the option that contradicts them.

๐Ÿ“Œ Risk Management:

  • If uncertain about an answer, consider skipping the question rather than guessing. This avoids the penalty associated with incorrect answers.

๐Ÿ”ท 4. Departmental Interview / Viva Voce Masterclass (Phase 2 Selection)

The interview process for the Sub Engineer (Electrical) role will assess both technical knowledge and behavioral competencies. Below are potential interview questions along with model answers.

๐Ÿ“Œ A. Technical Questions

  1. Question: Explain the working principle of an induction motor.
๐Ÿ’ก Model Answer:* An induction motor operates on the principle of electromagnetic induction. When AC supply is given to the stator winding, it produces a rotating magnetic field. This field induces current in the rotor, creating torque and causing the rotor to turn. The speed of the rotor is always less than the synchronous speed of the magnetic field, which is why it is called an induction motor.
  1. Question: What are the factors affecting the efficiency of a transformer?
๐Ÿ’ก Model Answer:* The efficiency of a transformer is influenced by copper losses (IยฒR losses), iron losses (hysteresis and eddy current losses), load conditions, and temperature. Proper design and material selection can minimize these losses, enhancing overall efficiency.

๐Ÿ“Œ B. Situational Questions

  1. Question: Describe a situation where you had to troubleshoot an electrical fault.
๐Ÿ’ก Model Answer:* In my previous role, we faced a sudden power failure in a section of the plant. I quickly conducted a systematic check, starting from the power source to the distribution panel. I identified a blown fuse due to an overload condition. After replacing the fuse and addressing the overload issue, I implemented a monitoring system to prevent future occurrences.
  1. Question: How would you handle a disagreement with a colleague regarding a technical solution?
๐Ÿ’ก Model Answer:* I believe in open communication and collaboration. I would discuss the differing viewpoints with my colleague, presenting data and reasoning to support my perspective. If necessary, I would involve a supervisor to mediate and ensure the best technical solution is implemented.

๐Ÿ“Œ C. Behavioral Questions

  1. Question: What motivates you to work in the electrical engineering field?
๐Ÿ’ก Model Answer:* My motivation stems from a passion for technology and problem-solving. I enjoy the challenge of designing and implementing electrical systems that enhance efficiency and safety. Contributing to projects that have a positive impact on society drives my commitment to this field.
  1. Question: Describe a time when you had to learn a new skill quickly.
๐Ÿ’ก Model Answer:* During a project, I was required to use a new software tool for circuit simulation. I dedicated extra hours to online tutorials and practice, enabling me to effectively utilize the software for our project within a week. This experience taught me the importance of adaptability and continuous learning.

๐Ÿ”ท 5. Recommended Standard Textbooks, Statutory Codes & Authoritative References

To achieve mastery in the subject area, candidates should refer to the following resources:

๐Ÿ“Œ Textbooks:

  • "Electrical Engineering: Principles and Applications" by Allan R. Hambley
  • "Fundamentals of Electric Circuits" by Charles K. Alexander and Matthew N. O. Sadiku
  • "Electrical Machines, Drives, and Power Systems" by Theodore Wildi

๐Ÿ“Œ Statutory Codes:

  • Pakistan Electric Power Regulatory Authority (NEPRA) Codes
  • International Electrotechnical Commission (IEC) Standards

๐Ÿ“Œ Authoritative References:

  • Pakistan Engineering Council (PEC) Guidelines
  • Local Electrical Safety Codes and Regulations

By following this comprehensive guide, candidates can effectively prepare for the Sub Engineer (Electrical) examination and excel in the selection process.

Q. 1 Electrical Engineering
Difficulty: Easy (1 Mark)
Kirchhoff's Current Law (KCL) at a junction in an electrical circuit is a direct mathematical consequence of which conservation law?
A
Conservation of Energy
B
Conservation of Electric Charge
โœ“ Correct
C
Conservation of Momentum
D
Conservation of Magnetic Flux
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
KCL states that the algebraic sum of currents entering a node is zero (ฮฃI = 0). Since current is the rate of flow of charge (dq/dt) and charge cannot accumulate at an infinitesimal node, KCL is based on the Conservation of Electric Charge.
Q. 2 Electrical Engineering
Difficulty: Easy (1 Mark)
Kirchhoff's Voltage Law (KVL) around any closed loop is based on the principle of conservation of:
A
Electric Charge
B
Energy
โœ“ Correct
C
Power
D
Mass
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
KVL states that the algebraic sum of all voltages around any closed loop in a circuit must equal zero (ฮฃV = 0). Because electric potential is energy per unit charge (V = W/Q), moving a charge around a closed path and returning to the same point results in zero net work done, embodying Conservation of Energy.
Q. 3 Electrical Engineering
Difficulty: Medium (1 Mark)
Thรฉvenin's equivalent resistance (Rth) of a linear circuit containing independent and dependent sources is found by:
A
Short-circuiting all voltage sources, open-circuiting all current sources, and calculating input impedance
B
Connecting an external test source (1 V or 1 A) at the terminals after deactivating only independent sources
โœ“ Correct
C
Taking the ratio of open-circuit voltage to maximum rated loop current
D
Short-circuiting independent current sources and open-circuiting independent voltage sources
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
When dependent sources are present in the circuit, they cannot be turned off. To determine Rth, all independent sources are deactivated (voltage sources shorted, current sources opened), an external test source (Vtest or Itest) is applied at the output terminals, and Rth = Vtest / Itest is calculated.
Q. 4 Electrical Engineering
Difficulty: Easy (1 Mark)
According to the Maximum Power Transfer Theorem, maximum power is transferred from a linear source network to a purely resistive load when:
A
The load resistance is equal to zero
B
The load resistance is infinitely large
C
The load resistance equals the Thรฉvenin equivalent resistance of the source (RL = Rth)
โœ“ Correct
D
The load resistance is half the Thรฉvenin equivalent resistance (RL = 0.5 Rth)
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
Differentiating load power P = I^2 * RL = [Vth / (Rth + RL)]^2 * RL with respect to RL and setting dP/dRL = 0 yields RL = Rth. At this condition, the maximum power transferred is Pmax = Vth^2 / (4 * Rth) with an efficiency of 50%.
Q. 5 Electrical Engineering
Difficulty: Medium (1 Mark)
In an AC circuit where the load impedance ZL = RL + jXL is connected to a source with internal impedance Zth = Rth + jXth, the condition for maximum power transfer is:
A
ZL = Zth
B
ZL = Zth* (complex conjugate: RL = Rth and XL = -Xth)
โœ“ Correct
C
RL = |Zth| and XL = 0
D
ZL = -Zth
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
For an AC circuit with adjustable load resistance and reactance, maximum power is delivered to the load when the load impedance is the complex conjugate of the source impedance: ZL = Zth*, meaning RL = Rth and XL = -Xth (cancelling the net reactive component).
Q. 6 Electrical Engineering
Difficulty: Easy (1 Mark)
Norton's equivalent circuit consists of:
A
An ideal voltage source in series with an impedance
B
An ideal current source in parallel with an impedance
โœ“ Correct
C
An ideal voltage source in parallel with an impedance
D
An ideal current source in series with an impedance
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
Norton's Theorem states that any linear, two-terminal circuit can be replaced by an equivalent circuit consisting of a Norton short-circuit current source (IN) connected in parallel with a Norton equivalent impedance (RN = Rth).
Q. 7 Electrical Engineering
Difficulty: Easy (1 Mark)
The Superposition Theorem is applicable only to circuits that are:
A
Non-linear and time-invariant
B
Linear and bilateral
โœ“ Correct
C
Non-linear with passive elements only
D
Unilateral and frequency-dependent
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
Superposition relies on the mathematical properties of homogeneity and additivity (linearity). Therefore, it is strictly applicable to linear and bilateral networks where response is directly proportional to excitation.
Q. 8 Electrical Engineering
Difficulty: Medium (1 Mark)
Why cannot the Superposition Theorem be used directly to calculate electric power in a circuit?
A
Power is a vector quantity
B
Power is proportional to the square of current or voltage (P = I^2*R or V^2/R), making it a non-linear relationship
โœ“ Correct
C
Power in AC circuits has a reactive component
D
Independent sources absorb power rather than deliver it
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
Power depends quadratically on current (I^2*R) or voltage (V^2/R). Because (I1 + I2)^2 != I1^2 + I2^2 due to the cross-term 2*I1*I2, power is a non-linear quantity, so Superposition cannot be applied directly to calculate power.
Q. 9 Electrical Engineering
Difficulty: Easy (1 Mark)
In a series RLC circuit at resonance, the total circuit impedance is:
A
Purely reactive and maximum
B
Purely resistive and minimum (Z = R)
โœ“ Correct
C
Equal to zero
D
Purely capacitive
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
At series resonance, the inductive reactance equals capacitive reactance (XL = XC), so net reactance is zero. The circuit impedance Z = sqrt(R^2 + (XL - XC)^2) simplifies to Z = R, which is its minimum possible value, leading to maximum current flow.
Q. 10 Electrical Engineering
Difficulty: Medium (1 Mark)
In a parallel RLC resonant circuit, the net impedance at resonance is:
A
Minimum and purely reactive
B
Maximum and purely resistive (Dynamic Resistance L / (C*R))
โœ“ Correct
C
Zero
D
Inductive
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
In a parallel RLC circuit (antiresonance), the circulating current between L and C is high while the line current drawn from the supply is minimum. Thus, impedance is maximum and purely resistive, termed dynamic impedance Z_dyn = L / (C * R).
Q. 11 Electrical Engineering
Difficulty: Medium (1 Mark)
The Quality Factor (Q-factor) of a series RLC resonant circuit is given by:
A
Q = R * sqrt(C / L)
B
Q = (1 / R) * sqrt(L / C)
โœ“ Correct
C
Q = (1 / R) * sqrt(C / L)
D
Q = R * sqrt(L / C)
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
For a series RLC circuit, Q = omega0 * L / R = (1 / (omega0 * C * R)). Substituting omega0 = 1 / sqrt(L * C) gives Q = (1 / R) * sqrt(L / C).
Q. 12 Electrical Engineering
Difficulty: Easy (1 Mark)
The bandwidth (BW) of a resonant circuit with resonant frequency f0 and quality factor Q is given by:
A
BW = f0 * Q
B
BW = f0 / Q
โœ“ Correct
C
BW = Q / f0
D
BW = sqrt(f0 * Q)
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
Bandwidth is defined as the frequency difference between half-power frequencies (f2 - f1). It is related to resonant frequency and Quality factor by BW = f0 / Q. A higher Q results in a narrower bandwidth and greater selectivity.
Q. 13 Electrical Engineering
Difficulty: Easy (1 Mark)
In a balanced 3-phase Star (Y) connected system, the relationship between line voltage (VL) and phase voltage (Vph) is:
A
VL = Vph
B
VL = sqrt(3) * Vph, and line voltage leads phase voltage by 30 degrees
โœ“ Correct
C
VL = Vph / sqrt(3)
D
VL = 3 * Vph
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
In a star connection, the line voltage is the phasor difference of two phase voltages: VL = sqrt(3) * Vph. In standard phase sequence, line voltage leads the corresponding phase voltage by 30 degrees, while line current equals phase current (IL = Iph).
Q. 14 Electrical Engineering
Difficulty: Easy (1 Mark)
In a balanced 3-phase Delta (ฮ”) connected system, the relationship between line current (IL) and phase current (Iph) is:
A
IL = Iph
B
IL = sqrt(3) * Iph, and line current lags phase current by 30 degrees
โœ“ Correct
C
IL = Iph / sqrt(3)
D
IL = 3 * Iph
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
In a delta connection, the voltages are identical across line and phase (VL = Vph), but line current is the phasor difference of two phase currents: IL = sqrt(3) * Iph. The line current lags the phase current by 30 degrees.
Q. 15 Electrical Engineering
Difficulty: Medium (1 Mark)
In the two-wattmeter method of measuring 3-phase active power, if one wattmeter reads zero and the other reads the total power, the power factor of the load is:
A
Unity (1.0)
B
0.5 lagging or leading
โœ“ Correct
C
0.866
D
Zero
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
The two wattmeter readings are W1 = VL*IL*cos(30 - phi) and W2 = VL*IL*cos(30 + phi). If phi = 60 degrees, cos(30 + 60) = cos(90) = 0, so W2 = 0. The power factor is cos(60) = 0.5.
Q. 16 Electrical Engineering
Difficulty: Easy (1 Mark)
If both wattmeters in the two-wattmeter method read equal positive values (W1 = W2), the load power factor is:
A
0.5
B
Unity (1.0)
โœ“ Correct
C
0 (purely reactive)
D
0.707
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
W1 = VL*IL*cos(30 - phi) and W2 = VL*IL*cos(30 + phi). For W1 = W2, cos(30 - phi) = cos(30 + phi), which requires phi = 0 degrees. Therefore, the power factor cos(phi) = cos(0) = 1.0 (unity).
Q. 17 Electrical Engineering
Difficulty: Medium (1 Mark)
If one wattmeter reads positive and the other reads an equal negative value (W1 = -W2), the power factor of the load is:
A
Unity (1.0)
B
0.5
C
Zero (phi = 90 degrees)
โœ“ Correct
D
0.866
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
Total active power P = W1 + W2 = 0. Because W1 = -W2, tan(phi) = sqrt(3)*(W1 - W2)/(W1 + W2) = infinity, giving phi = 90 degrees and power factor cos(90) = 0 (purely inductive or capacitive load).
Q. 18 Electrical Engineering
Difficulty: Easy (1 Mark)
Three identical resistors each of resistance R are connected in Delta. Their equivalent Star-connected resistance per phase is:
A
3 * R
B
R / 3
โœ“ Correct
C
R / 9
D
R
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
In Delta-to-Star transformation, R_star = (R * R) / (R + R + R) = R^2 / (3R) = R / 3. Conversely, Star-to-Delta gives R_delta = 3 * R_star.
Q. 19 Electrical Engineering
Difficulty: Medium (1 Mark)
Millman's Theorem is primarily used to determine:
A
The current through a non-linear diode
B
The common terminal voltage across multiple parallel branches containing voltage sources and internal impedances
โœ“ Correct
C
The resonance frequency of coupled circuits
D
The transient response of an RL network
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
Millman's Theorem states that when a number of voltage sources with series impedances are connected in parallel, the equivalent voltage across the common terminals is V_eq = (ฮฃ Vi * Yi) / (ฮฃ Yi), where Yi is the admittance of each branch.
Q. 20 Electrical Engineering
Difficulty: Hard (1 Mark)
Tellegen's Theorem applies to any electrical network as long as:
A
The network elements are linear, time-invariant, and bilateral
B
The network obeys Kirchhoff's Current Law and Kirchhoff's Voltage Law, regardless of element linearity or time variance
โœ“ Correct
C
The network operates exclusively on sinusoidal AC steady-state
D
The network does not contain any independent current sources
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
Tellegen's Theorem is based purely on KCL and KVL topology. It states that the algebraic sum of power in all branches is zero (ฮฃ vk * ik = 0), valid for linear, non-linear, time-variant, time-invariant, active, or passive networks.
Q. 21 Electrical Engineering
Difficulty: Easy (1 Mark)
The time constant of a series RL circuit is defined as:
A
tau = R / L
B
tau = L / R
โœ“ Correct
C
tau = L * R
D
tau = 1 / (L * R)
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
In an RL circuit, current builds up as i(t) = (V/R) * (1 - e^(-t / tau)), where the time constant tau = L / R. In one time constant, the current reaches 63.2% of its steady-state maximum value.
Q. 22 Electrical Engineering
Difficulty: Easy (1 Mark)
The time constant of a series RC circuit is given by:
A
tau = R / C
B
tau = C / R
C
tau = R * C
โœ“ Correct
D
tau = 1 / (R * C)
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
In an RC circuit, the charging voltage across the capacitor is v_C(t) = V * (1 - e^(-t / tau)), where tau = R * C. It takes approximately 5 time constants (5 * tau) for the capacitor to reach 99.3% of full charge.
Q. 23 Electrical Engineering
Difficulty: Easy (1 Mark)
At steady-state in a DC circuit, an ideal inductor behaves as a(n):
A
Open circuit
B
Short circuit
โœ“ Correct
C
Constant current source
D
Pure capacitor
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
For an inductor, voltage v = L * (di/dt). Under DC steady-state, current is constant (di/dt = 0), so voltage drop across the inductor is zero, meaning it behaves as an ideal short circuit.
Q. 24 Electrical Engineering
Difficulty: Easy (1 Mark)
At steady-state in a DC circuit, an ideal capacitor behaves as a(n):
A
Short circuit
B
Open circuit
โœ“ Correct
C
Zero-ohm resistor
D
Inductive reactor
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
For a capacitor, current i = C * (dv/dt). Under DC steady-state, voltage is constant (dv/dt = 0), so current through the capacitor is zero, meaning it behaves as an open circuit.
Q. 25 Electrical Engineering
Difficulty: Easy (1 Mark)
The form factor of a pure sinusoidal alternating wave is defined as the ratio of:
A
Peak value to RMS value (1.414)
B
RMS value to Average value (1.11)
โœ“ Correct
C
Average value to Peak value (0.637)
D
Peak-to-peak value to RMS value (2.828)
๐Ÿ’ก Step-by-Step Explanation & Concept Rationale
Form Factor = RMS Value / Average Value. For a sine wave, V_rms = Vm / sqrt(2) = 0.707 Vm, and V_avg = 2 * Vm / pi = 0.637 Vm. Form Factor = (Vm / sqrt(2)) / (2 Vm / pi) = pi / (2 * sqrt(2)) โ‰ˆ 1.11.
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